In a code language, 'DANCER' is coded as 'REPEAD' and 'QUEAZY' is coded as 'YZGCUQ'. How will 'SQUAWK' be coded in the same language?

Let's decode the shifting mechanism used in the pattern:
First code: DANCER → REPEAD
Let's see how letters swap or change positions:

The first letter D goes to the last position.

The last letter R goes to the first position.

The remaining internal letters ANCE are reversed or modified. Let's look closely at the arrangement:

1
st
and last letters swap places: D⟷R

The inner letters are A, N, C, E. In the code, the inner letters are E, P, E, A.
Let's check position-wise transformations:

D→R (Last letter becomes first)

A→E (1+4=5)

N→P (14+2=16)

C→E (3+2=5)

E→A (5−4=1)

R→D (First letter becomes last)

Let's check an alternative pattern involving complete reverse order:
The reverse of DANCER is R E C N A D.
Now let's compare R E C N A D with R E P E A D:

1
st
letter: R → R (No change)

2
nd
letter: E → E (No change)

3
rd
letter: C (3) +2=E (5) → wait, code is P. Let's re-verify:
Let's map letter by letter from DANCER to REPEAD:

D→R

A→E

N→P

C→E

E→A

R→D

Let's test the second pair: QUEAZY → YZGCUQ

Q→Y

U→Z

E→G

A→C

Z→U

Y→Q

Notice that the first two letters and last two letters are interchanged in reverse order!
In DANCER:

Last two letters are ER → written at the front as RE.

First two letters are DA → written at the end as AD.

Middle letters are NC → modified as +2: N+2=P, C+2=E→PE.
Putting it together: RE + PE + AD = REPEAD.

Let's double-check this with QUEAZY:

Last two letters ZY → written at the front as YZ.

First two letters QU → written at the end as UQ.

Middle letters EA → modified as +2: E+2=G, A+2=C→GC.
Putting it together: YZ + GC + UQ = YZGCUQ. This matches perfectly!

Applying this logic to SQUAWK:

Last two letters WK → written at the front as KW.

First two letters SQ → written at the end as QS.

Middle letters UA → modified as +2: U+2=W, A+2=C→WC.

Combining these pieces gives KWWCQS.