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In a cross between a male and female, both heterozygous for sickle cell anaemia gene, what percentage of the progeny will be diseased?

  1. A
    25%
  2. B
    100%
  3. C
    50%
  4. D
    75%

Solution & Step-by-step Explanation

Sickle cell anaemia is an autosomal recessive disorder. Let Hb
A
be normal and Hb
S
be the sickle allele.
Heterozygous parents: Hb
A
Hb
S
×Hb
A
Hb
S
.
Progeny genotypes:

1/4 Hb
A
Hb
A
(Normal)

2/4 Hb
A
Hb
S
(Carriers)

1/4 Hb
S
Hb
S
(Diseased)
The percentage of diseased progeny is 1/4=25%.

Practice this question

Try it yourself before checking the explanation above.

In a cross between a male and female, both heterozygous for sickle cell anaemia gene, what percentage of the progeny will be diseased?
A
25%
B
100%
C
50%
D
75%

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geneticspedigree/disease

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