In a face centred cubic lattice, atom A occupies the corner positions and atom B occupies the face centre positions. If one atom of B is missing from - Chemistry MCQ FIITJEE AIEEE 2011 (Set Q) 2026 | ExamTest.live | ExamTest.live

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In a face centred cubic lattice, atom A occupies the corner positions and atom B occupies the face centre positions. If one atom of B is missing from one of the face centred points, the formula of the compound is:

A $AB_{2}$
B $A_{2} B_{3}$
C $A_{2} B_{5}$
D $A_{2} B$

Solution & Step-by-step Explanation

1. Corners: 8 \times 1/8 = 1 atom of A.2. Face centres: Total face centres = 6 . If 1 is missing, 5 remain.Contribution = 5 \times 1/2 = 2.5 atoms of B.Formula: A_{1} B_{2.5} \to A_{2} B_{5} .

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In a face centred cubic lattice, atom A occupies the corner positions and atom B occupies the face centre positions. If one atom of B is missing from one of the face centred points, the formula of the compound is:

A

AB_{2}

B

A_{2} B_{3}

C

A_{2} B_{5}

D

A_{2} B

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