In a group of cows and hens, the number of legs are $14$ more than twice the number of heads. How many cows are there?

Let the number of cows be $x$ and the number of hens be $y$.
Total number of heads = $x+y$
Total number of legs = $4x+2y$ (since a cow has 4 legs and a hen has 2 legs)

According to the given condition:

$$4x+2y=2(x+y)+14$$

$$4x+2y=2x+2y+14$$

Subtracting $2y$ from both sides:

$$4x=2x+14$$

$$2x=14$$

$$x=7$$

Thus, there are $7$ cows.