In a group of cows and hens, the total number of legs is $14$ more than twice the total number of heads. The number of cows in the group is:

Let the total number of cows be $C$ and the number of hens be $H$.
We can formulate expressions for total heads and total legs:

$$\text{Total Heads}=C+H$$

$$\text{Total Legs}=4C+2H$$

According to the given condition:

$$\text{Total Legs}=2\times (\text{Total Heads})+14$$

$$4C+2H=2(C+H)+14$$

Expand and simplify the algebraic equation:

$$4C+2H=2C+2H+14$$

Subtract $2H$ from both sides:

$$4C=2C+14$$

$$2C=14$$

$$C=7$$

Hence, the number of cows is $7$.