In a medical institute, the strength of the students in the first two classes are in the ratio of 8:17. The ratio of the number of students in the second and the third classes is 2:3. What is the average of the number of students in the first and third classes, if the number of students in the second class is 612?
- A288
- B828
- C603
- D918
Solution & Step-by-step Explanation
Let the three classes be denoted as C
1
, C
2
, and C
3
.
Given ratios:
C
2
C
1
=
17
8
C
3
C
2
=
3
2
To combine the ratios, let's make the term for C
2
common by multiplying the first ratio by 2 and the second ratio by 17:
C
1
:C
2
=8×2:17×2=16:34
C
2
:C
3
=2×17:3×17=34:51
So, the combined ratio is:
C
1
:C
2
:C
3
=16:34:51
We are given that the number of students in the second class C
2
=612:
34k=612⟹k=
34
612
=18
Now, we calculate the strength of the first and third classes:
C
1
=16×18=288
C
3
=51×18=918
The average of the number of students in the first and third classes is:
Average=
2
C
1
+C
3
=
2
288+918
=
2
1206
=603
1
, C
2
, and C
3
.
Given ratios:
C
2
C
1
=
17
8
C
3
C
2
=
3
2
To combine the ratios, let's make the term for C
2
common by multiplying the first ratio by 2 and the second ratio by 17:
C
1
:C
2
=8×2:17×2=16:34
C
2
:C
3
=2×17:3×17=34:51
So, the combined ratio is:
C
1
:C
2
:C
3
=16:34:51
We are given that the number of students in the second class C
2
=612:
34k=612⟹k=
34
612
=18
Now, we calculate the strength of the first and third classes:
C
1
=16×18=288
C
3
=51×18=918
The average of the number of students in the first and third classes is:
Average=
2
C
1
+C
3
=
2
288+918
=
2
1206
=603