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In a medical institute, the strength of the students in the first two classes are in the ratio of 8:17. The ratio of the number of students in the second and the third classes is 2:3. What is the average of the number of students in the first and third classes, if the number of students in the second class is 612?

  1. A
    288
  2. B
    828
  3. C
    603
  4. D
    918

Solution & Step-by-step Explanation

Let the three classes be denoted as C
1

, C
2

, and C
3

.
Given ratios:

C
2


C
1



=
17
8


C
3


C
2



=
3
2


To combine the ratios, let's make the term for C
2

common by multiplying the first ratio by 2 and the second ratio by 17:

C
1

:C
2

=8×2:17×2=16:34
C
2

:C
3

=2×17:3×17=34:51
So, the combined ratio is:

C
1

:C
2

:C
3

=16:34:51
We are given that the number of students in the second class C
2

=612:

34k=612⟹k=
34
612

=18
Now, we calculate the strength of the first and third classes:

C
1

=16×18=288
C
3

=51×18=918
The average of the number of students in the first and third classes is:

Average=
2
C
1

+C
3



=
2
288+918

=
2
1206

=603

Practice this question

Try it yourself before checking the explanation above.

In a medical institute, the strength of the students in the first two classes are in the ratio of 8:17. The ratio of the number of students in the second and the third classes is 2:3. What is the average of the number of students in the first and third classes, if the number of students in the second class is 612?
A
288
B
828
C
603
D
918

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