In a mixture, water and milk are in the ratio of 3:5. In the second mixture, the ratio of water and milk is 9:11. If these two mixtures are mixed to form a new mixture in which water and milk are in the ratio 5:7, then what is the ratio of these two mixtures in the new mixture?
- A1 : 2
- B3 : 2
- C4 : 5
- D4 : 7
Solution & Step-by-step Explanation
Let's solve this using the method of Alligation by focusing on the proportion of water in each mixture.
Proportion of water in the 1st mixture (m
1
) =
3+5
3
=
8
3
Proportion of water in the 2nd mixture (m
2
) =
9+11
9
=
20
9
Proportion of water in the final mixture (m
f
) =
5+7
5
=
12
5
To simplify calculations, find the LCM of the denominators (8,20,12), which is 120.
Multiply each proportion by 120:
Value for 1st mixture =
8
3
×120=45
Value for 2nd mixture =
20
9
×120=54
Mean value =
12
5
×120=50
Now apply alligation rule:
Mixture 1 (45) Mixture 2 (54)
\ /
(50)
/ \
(54 - 50) (50 - 45)
= 4 = 5
Thus, the required ratio is 4:5.
Proportion of water in the 1st mixture (m
1
) =
3+5
3
=
8
3
Proportion of water in the 2nd mixture (m
2
) =
9+11
9
=
20
9
Proportion of water in the final mixture (m
f
) =
5+7
5
=
12
5
To simplify calculations, find the LCM of the denominators (8,20,12), which is 120.
Multiply each proportion by 120:
Value for 1st mixture =
8
3
×120=45
Value for 2nd mixture =
20
9
×120=54
Mean value =
12
5
×120=50
Now apply alligation rule:
Mixture 1 (45) Mixture 2 (54)
\ /
(50)
/ \
(54 - 50) (50 - 45)
= 4 = 5
Thus, the required ratio is 4:5.