In a triangle ABC , let C = π/2 . If r is the inradius and R is the circumradius of the triangle, then 2(r + R) equals: - Mathematics MCQ AIEEE 2026 | ExamTest.live

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In a triangle A BC, let ∠ C = \frac{π}{2} . If r is the inradius and R is the circumradius of the triangle, then 2 (r + R) equals:

Solution & Step-by-step Explanation

In a right-angled triangle at C :Circumradius R = \frac{c}{2} (since the hypotenuse is the diameter).Inradius r = \frac{a + b - c}{2} .Therefore: r + R = \frac{a + b - c}{2} + \frac{c}{2} = \frac{a + b}{2} 2 (r + R) = a + b

Try it yourself before checking the explanation above.

In a triangle A BC, let ∠ C = \frac{π}{2} . If r is the inradius and R is the circumradius of the triangle, then 2 (r + R) equals:

b + c

a + b

a + b + c

c + a

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