In an election, there were only two candidates. 12% of the voters did not cast their votes. The winner by obtaining 60% of the total votes defeated his opposite contestant by 1200 votes. Find the total number of votes.
- A4000
- B3750
- C5730
- D3570
Solution & Step-by-step Explanation
Let the total number of registered votes be 100%.
Voters who did not cast votes = 12%
Total cast votes = 100%−12%=88%
The winner obtained 60% of the total votes.
Winner's votes = 60%
Since total cast votes are 88%, the remaining cast votes go to the defeated contestant:
Loser's votes = Total cast votes−Winner’s votes=88%−60%=28%
The winner defeated the opposite candidate by 1200 votes. Thus, the difference in percentage of votes is:
Winner’s votes−Loser’s votes=60%−28%=32%
According to the question:
32% of total votes=1200
1% of total votes=
32
1200
=37.5
Total number of votes (100%)=37.5×100=3750
Voters who did not cast votes = 12%
Total cast votes = 100%−12%=88%
The winner obtained 60% of the total votes.
Winner's votes = 60%
Since total cast votes are 88%, the remaining cast votes go to the defeated contestant:
Loser's votes = Total cast votes−Winner’s votes=88%−60%=28%
The winner defeated the opposite candidate by 1200 votes. Thus, the difference in percentage of votes is:
Winner’s votes−Loser’s votes=60%−28%=32%
According to the question:
32% of total votes=1200
1% of total votes=
32
1200
=37.5
Total number of votes (100%)=37.5×100=3750