In an ellipse, the distance between its foci is 6 and the minor axis is 8 . Then its eccentricity is: - Mathematics MCQ AIEEE 2006 2026 | ExamTest.live

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In an ellipse, the distance between its foci is 6 and the minor axis is 8 . Then its eccentricity is:

Solution & Step-by-step Explanation

Distance between foci = 2 a e = 6 ⟹ a e = 3 Length of minor axis = 2 b = 8 ⟹ b = 4 Relationship: b^{2} = a^{2} (1 - e^{2}) = a^{2} - a^{2} e^{2} 16 = a^{2} - (3)^{2} a^{2} = 16 + 9 = 25 ⟹ a = 5 Now, a e = 3 ⟹ 5 e = 3 ⟹ e = 3/5 .

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In an ellipse, the distance between its foci is 6 and the minor axis is 8 . Then its eccentricity is:

3/5

1/2

4/5

1/5

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