In an examination, $35\%$ of students fail in Mathematics and $15\%$ fail in English. If $10\%$ fail in both subjects, the total pass percentage is:

Let's calculate the total percentage of students who failed in at least one subject using the principle of set inclusion-exclusion:
$$\text{Total Failed Percentage}=\%\text{Fail}(M)+\%\text{Fail}(E)-\%\text{Fail}(M\cap E)$$

$$\text{Total Failed Percentage}=35\%+15\%-10\%=40\%$$

Since $40\%$ of the total students failed the examination, the overall percentage of students who passed is:

$$\text{Pass Percentage}=100\%-40\%=60\%$$