In an ideal transformer, the turns ratio N_p/N_s = 1/2 . The ratio V_s : V_p is equal to (the symbols carry their usual meaning): - Physics MCQ NEET (UG) 2024 2026 | ExamTest.live

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In an ideal transformer, the turns ratio \frac{N _{p}}{N _{s}} = \frac{1}{2} . The ratio V_{s} : V_{p} is equal to (the symbols carry their usual meaning):

Solution & Step-by-step Explanation

For an ideal transformer, the relationship between the number of turns and the voltage is: \frac{V _{s}}{V _{p}} = \frac{N _{s}}{N _{p}} Given \frac{N _{p}}{N _{s}} = \frac{1}{2}, taking the reciprocal gives \frac{N _{s}}{N _{p}} = \frac{2}{1} .Therefore: \frac{V _{s}}{V _{p}} = \frac{2}{1} The ratio V_{s} : V_{p} is 2 : 1 .

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In an ideal transformer, the turns ratio \frac{N _{p}}{N _{s}} = \frac{1}{2} . The ratio V_{s} : V_{p} is equal to (the symbols carry their usual meaning):

1 : 2

2 : 1

1 : 1

1 : 4

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