In an LCR circuit as shown below both switches are open initially. Now switch S_1 is closed, S_2 kept open. ( q is charge on the capacitor and = RC is capacitive time constant). Which of the following statement is correct? ![image](https://pub-7faa453bd1ec4bf0a04cc031c6f058de.r2.dev/images/65590977-

In an LCR circuit as shown below both switches are open initially. Now switch S_1 is closed, S_2 kept open. ( q is charge on the capacitor and = RC is - Physics MCQ JEE Main 2026 | ExamTest.live

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In an LCR circuit as shown below both switches are open initially. Now switch S_{1} is closed, S_{2} kept open. (q is charge on the capacitor and τ = RC is capacitive time constant). Which of the following statement is correct?

When S_{1} is closed and S_{2} is open, the circuit is a simple charging RC circuit. The charge q on the capacitor at time t is given by: q (t) = C V (1 - e^{- t / RC}) = C V (1 - e^{- t / τ}) At t = 2 τ : q = C V (1 - e^{- 2 τ / τ}) = C V (1 - e^{- 2}) .This matches Option B.

Try it yourself before checking the explanation above.

In an LCR circuit as shown below both switches are open initially. Now switch S_{1} is closed, S_{2} kept open. (q is charge on the capacitor and τ = RC is capacitive time constant). Which of the following statement is correct?

At t = τ, q = C V /2

At t = 2 τ, q = C V (1 - e^{- 2})

At t = \frac{τ}{2}, q = C V (1 - e^{- 1/2})

Work done by the battery is half of the energy dissipated in the resistor.

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