In Dumas' method of estimation of nitrogen 0.35 g of an organic compound gave 55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. Th - Chemistry MCQ Chemistry | ExamTest.live

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In Dumas' method of estimation of nitrogen 0.35 g of an organic compound gave 55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentage composition of nitrogen in the compound would be: (Aqueous tension at 300 K = 15 mm)

Solution & Step-by-step Explanation

1. Pressure of dry nitrogen P_{1} = 715 - 15 = 700 mm .2. Convert Volume to STP (V_{2}): \frac{P _{1} V _{1}}{T _{1}} = \frac{P _{2} V _{2}}{T _{2}} \Rightarrow \frac{700 \times 55}{300} = \frac{760 \times V _{2}}{273} V_{2} = \frac{700 \times 55 \times 273}{300 \times 760} \approx 46.09 mL 3. Percentage of Nitrogen: % N = \frac{28}{22400} \times \frac{V _{STP}}{mass of compound} \times 100 % N = \frac{28}{22400} \times \frac{46.09}{0.35} \times 100 \approx 16.45%

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In Dumas' method of estimation of nitrogen 0.35 g of an organic compound gave 55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentage composition of nitrogen in the compound would be: (Aqueous tension at 300 K = 15 mm)

14.45%

15.45%

16.45%

17.45%

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