In how much time (in years) will ₹8,000 amount to ₹9,159.20 at 14% per annum interest compounded half yearly?
- A2
- B3
- C4
- D1
Solution & Step-by-step Explanation
Given:
Principal (P) = ₹8,000
Amount (A) = ₹9,159.20
Annual Rate (R) = 14%
Since the interest is compounded half-yearly:
Rate per half-year (R
′
) =
2
14%
=7%=0.07
Let n be the number of half-yearly periods.
The compound interest formula is:
A=P(1+
100
R
′
)
n
9,159.20=8,000×(1+0.07)
n
8,000
9,159.20
=(1.07)
n
80,000
91,592
=(1.07)
n
Divide both numerator and denominator by 8,000:
80,000÷8
91,592÷8
=
10,000
11,449
=1.1449
So we have:
1.1449=(1.07)
n
Since (1.07)
2
=1.1449, it follows that:
n=2half-yearly periods
Converting half-yearly periods into years:
Time=
2
2
=1year
Principal (P) = ₹8,000
Amount (A) = ₹9,159.20
Annual Rate (R) = 14%
Since the interest is compounded half-yearly:
Rate per half-year (R
′
) =
2
14%
=7%=0.07
Let n be the number of half-yearly periods.
The compound interest formula is:
A=P(1+
100
R
′
)
n
9,159.20=8,000×(1+0.07)
n
8,000
9,159.20
=(1.07)
n
80,000
91,592
=(1.07)
n
Divide both numerator and denominator by 8,000:
80,000÷8
91,592÷8
=
10,000
11,449
=1.1449
So we have:
1.1449=(1.07)
n
Since (1.07)
2
=1.1449, it follows that:
n=2half-yearly periods
Converting half-yearly periods into years:
Time=
2
2
=1year