In hydrogen spectrum, the shortest wavelength in the Balmer series is λ . The shortest wavelength in the Brackett series is: - Physics MCQ NEET 2023 2026 | ExamTest.live

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In hydrogen spectrum, the shortest wavelength in the Balmer series is λ . The shortest wavelength in the Brackett series is:

Solution & Step-by-step Explanation

The wavelength λ in the hydrogen spectrum is given by: \frac{1}{λ} = R [\frac{1}{n _{1}^{2}} - \frac{1}{n _{2}^{2}}] The shortest wavelength occurs when n_{2} = \infty .Balmer series (n_{1} = 2): \frac{1}{λ} = R [\frac{1}{2 ^{2}} - \frac{1}{\infty ^{2}}] = \frac{R}{4} ⟹ λ = \frac{4}{R} Brackett series (n_{1} = 4): \frac{1}{λ ^{'}} = R [\frac{1}{4 ^{2}} - \frac{1}{\infty ^{2}}] = \frac{R}{16} λ^{'} = \frac{16}{R} = 4 (\frac{4}{R}) = 4 λ

Try it yourself before checking the explanation above.

In hydrogen spectrum, the shortest wavelength in the Balmer series is λ . The shortest wavelength in the Brackett series is:

2 λ

4 λ

9 λ

16 λ

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