In mixture A, there is 5 L of syrup in 6 L of water. In mixture B, there is 3.5 L of syrup in 5.5 L of water. In which of the two mixtures is the conc - Quantitative Aptitude MCQ Competitive Exam Practice 2026 | ExamTest.live

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In mixture A, there is 5 L of syrup in 6 L of water. In mixture B, there is 3.5 L of syrup in 5.5 L of water. In which of the two mixtures is the concentration of syrup greater?

A $more information is required to be able to determine where the concentration of syrup is more$
B $the concentration of syrup is same in both A and B$
C $B$
D $A$

Solution & Step-by-step Explanation

Concentration of syrup is measured as \frac{Volume of Syrup}{Total Volume of Mixture (Syrup + Water)} .For Mixture A: Syrup = 5 L, Water = 6 L ⟹ Total Volume = 5 + 6 = 11 L Concentration_{A} = \frac{5}{11} \approx 0.4545 or 45.45% For Mixture B: Syrup = 3.5 L, Water = 5.5 L ⟹ Total Volume = 3.5 + 5.5 = 9 L Concentration_{B} = \frac{3.5}{9} = \frac{35}{90} \approx 0.3888 or 38.89% Comparing the two, Concentration_{A} > Concentration_{B} . Thus, the concentration of syrup is greater in Mixture A.

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In mixture A, there is 5 L of syrup in 6 L of water. In mixture B, there is 3.5 L of syrup in 5.5 L of water. In which of the two mixtures is the concentration of syrup greater?

more information is required to be able to determine where the concentration of syrup is more

the concentration of syrup is same in both A and B

B

A

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