In nine games, A wins five games with score differences of 12, 3, 8, 4 and 1, while in the remaining four games, he loses with score differences of -4, -1, -2 and -3. The average score difference of A in all the nine games is:
- A2
- B3
- C4
- D1
Solution & Step-by-step Explanation
To find the average score difference across all nine games, we first calculate the total sum of the score differences.
Sum of score differences in won games:
12+3+8+4+1=28
Sum of score differences in lost games:
(−4)+(−1)+(−2)+(−3)=−10
Total sum of score differences for all 9 games:
Total Sum=28+(−10)=18
Total number of games = 9
Average Score Difference=
Total Games
Total Sum
=
9
18
=2
Sum of score differences in won games:
12+3+8+4+1=28
Sum of score differences in lost games:
(−4)+(−1)+(−2)+(−3)=−10
Total sum of score differences for all 9 games:
Total Sum=28+(−10)=18
Total number of games = 9
Average Score Difference=
Total Games
Total Sum
=
9
18
=2