In the circuit shown below, the voltage and current sources are ideal. The voltage V ₒᵤₜ across the current source, in volts, is
- A0
- B5
- C10
- D20
Solution & Step-by-step Explanation
Concept:
Kirchoff’s second law :
- This law is also known as loop rule or voltage law ( KVL) and according to it “thealgebraic sum of the changes in potential in the complete traversal of a mesh (closed-loop) is zero” , i.e. Σ V = 0 .
- This law represents “conservation of energy” as if the sum of potential changes around a closed loop is not zero , unlimited energy could be gained by repeatedly carrying a charge around a loop.
For any load, current enter through positive polarity and exit from negative polarity and for source it will be reversed.
Calculation:
Apply KVL in the loop as shown below,
The current flow through 2 Ω is 5 A as shown in fig and it will give a drop of 10 V.
From the figure we get,
V ₒᵤₜ + 10 + 10 = 0
V out = 20 V
Kirchoff’s second law :
- This law is also known as loop rule or voltage law ( KVL) and according to it “thealgebraic sum of the changes in potential in the complete traversal of a mesh (closed-loop) is zero” , i.e. Σ V = 0 .
- This law represents “conservation of energy” as if the sum of potential changes around a closed loop is not zero , unlimited energy could be gained by repeatedly carrying a charge around a loop.
For any load, current enter through positive polarity and exit from negative polarity and for source it will be reversed.
Calculation:
Apply KVL in the loop as shown below,
The current flow through 2 Ω is 5 A as shown in fig and it will give a drop of 10 V.
From the figure we get,
V ₒᵤₜ + 10 + 10 = 0
V out = 20 V