In the circuit shown in the figure, the input voltage V_i is 20 V , V_BE = 0 and V_CE = 0 . If R_B = 500 kΩ and R_C = 4 kΩ , the values of I_B, I_C and β are given by: ![image](https://pub-7faa453bd1ec4bf0a04cc031c6f058de.r2.dev/images/912b0103-0024-4e75-9b02-12ab90a5eb05.png)

In the circuit shown in the figure, the input voltage V_i is 20 V , V_BE = 0 and V_CE = 0 . If R_B = 500 kΩ and R_C = 4 kΩ , the values of I_B, I_C an - Physics MCQ NEET (UG) 2018 2026 | ExamTest.live

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In the circuit shown in the figure, the input voltage V_{i} is 20 V, V_{BE} = 0 and V_{CE} = 0 . If R_{B} = 500 k Ω and R_{C} = 4 k Ω, the values of I_{B}, I_{C} and β are given by:

1. Input loop: V_{i} = I_{B} R_{B} + V_{BE} Given V_{BE} = 0 : 20 = I_{B} \times 500 \times 1 0^{3} ⟹ I_{B} = \frac{20}{5 \times 1 0 ^{5}} = 4 \times 1 0^{- 5} A = 40 μ A 2. Output loop: V_{CC} = I_{C} R_{C} + V_{CE} (assuming V_{CC} = V_{i} = 20 V)Given V_{CE} = 0 : 20 = I_{C} \times 4 \times 1 0^{3} ⟹ I_{C} = \frac{20}{4 \times 1 0 ^{3}} = 5 \times 1 0^{- 3} A = 5 mA 3. Current gain β : β = \frac{I _{C}}{I _{B}} = \frac{5 \times 1 0 ^{- 3}}{40 \times 1 0 ^{- 6}} = \frac{5000}{40} = 125

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In the circuit shown in the figure, the input voltage V_{i} is 20 V, V_{BE} = 0 and V_{CE} = 0 . If R_{B} = 500 k Ω and R_{C} = 4 k Ω, the values of I_{B}, I_{C} and β are given by:

I_{B} = 20 μ A, I_{C} = 5 mA, β = 250

I_{B} = 25 μ A, I_{C} = 5 mA, β = 200

I_{B} = 40 μ A, I_{C} = 10 mA, β = 250

I_{B} = 40 μ A, I_{C} = 5 mA, β = 125

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