In the circuit shown, the input Vi is a sinusoidal AC voltage having an RMS value of 230 V ± 20%. The worst-case peak-inverse voltage seen across any - Electrical Engineering NAT PYQs Based test 23: Power Electronics | ExamTest.live

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2 marks

In the circuit shown, the input Vi is a sinusoidal AC voltage having an RMS value of 230 V \pm 20%. The worst-case peak-inverse voltage seen across any diode is ______V. (Round off to 2 decimal places).

Correct Answer

389-391

Solution & Step-by-step Explanation

Concept: The maximum voltage across a reverse bias diode is known as Peak Inverse Voltage. PIV for different rectifiers is shown below: - Half Wave rectifier: Vm - Full Wave centre tap rectifier: 2Vm - Full Wave Bridge rectifier : Vm Calculation: The given circuit is a full-wave bridge rectifier. Given input Vi is a sinusoidal AC voltage having an RMS value of V_{r m s} = 230 V \pm 20% The worst-case peak-inverse voltage seen across any diode is Vm = \sqrt2 \times maximum value of V_{r m s} V_{m} = \sqrt2 \times (230 + 0.2 \times 230) **V_{m} = 390.32 V Important Points** CIRCUIT Number of Diodes Average DC Voltage (Vdc) RMS Current (Irms) Peak Inverse Voltage (PIV) Half-Wave Rectifier 1 \frac{V _{m}}{π} \frac{I _{m}}{2} V_{m} Center-Tap Full Wave Rectifier 2 \frac{2 V _{m}}{π} \frac{I _{m}}{2} 2 V_{m} Bridge-Type Full Wave Rectifier 4 \frac{2 V _{m}}{π} \frac{I _{m}}{2} V_{m}

CIRCUIT	Number of Diodes	Average DC Voltage (Vdc)	RMS Current (Irms)	Peak Inverse Voltage (PIV)
Half-Wave Rectifier	1	$\frac{V _{m}}{π}$	$\frac{I _{m}}{2}$	$V_{m}$
Center-Tap Full Wave Rectifier	2	$\frac{2 V _{m}}{π}$	$\frac{I _{m}}{2}$	$2 V_{m}$
Bridge-Type Full Wave Rectifier	4	$\frac{2 V _{m}}{π}$	$\frac{I _{m}}{2}$	$V_{m}$

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In the circuit shown, the input Vi is a sinusoidal AC voltage having an RMS value of 230 V \pm 20%. The worst-case peak-inverse voltage seen across any diode is ______V. (Round off to 2 decimal places).

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