In the following question, which one set of letters when sequentially placed at the gaps in the given letter series shall complete it?
ab_d_bb_a_bd
- Abadd
- Bbabd
- Cbadb
- Dabdd
Solution & Step-by-step Explanation
The total length of the sequence including gaps is 12 letters. Let's test dividing it into four groups of 3 letters each: ab_ | d_b | b_a | _bd
Let's check option C (badb):
First blank: b → abb
Second blank: a → dab
Third blank: d → bda
Fourth blank: b → bbd
This does not form a repeating sequence.
Let's test option A (badd):
Sequence becomes: ab + b + d + a + bb + d + a + d + bd → abbdabbdabbd
Let's check the repeating pattern:
abbd | abbd | abbd
The pattern perfectly repeats the 4-letter block abbd. The letters filled in the gaps are b, a, d, d.
Let's check option C (badb):
First blank: b → abb
Second blank: a → dab
Third blank: d → bda
Fourth blank: b → bbd
This does not form a repeating sequence.
Let's test option A (badd):
Sequence becomes: ab + b + d + a + bb + d + a + d + bd → abbdabbdabbd
Let's check the repeating pattern:
abbd | abbd | abbd
The pattern perfectly repeats the 4-letter block abbd. The letters filled in the gaps are b, a, d, d.