In the following question, which one set of letters when sequentially placed at the gaps in the given letter series shall complete it?
_ k _ m _ k l _ j k _ m
- Ajljlm
- Bjljml
- Cjllmj
- Djllmm
Solution & Step-by-step Explanation
The total length of the sequence including gaps is 12 characters. We can divide it into groups of 4:
_ k _ m | _ k l _ | j k _ m
By comparing the blocks:
From the third block j k _ m, we can infer that the first letter of each block is 'j' and the third letter is 'l'.
Filling this pattern j k l m into all blocks:
1st block: j k l m
2nd block: j k l m
3rd block: j k l m
The sequence of inserted letters is: j, l, j, m, l.
This matches option B (jljml).
_ k _ m | _ k l _ | j k _ m
By comparing the blocks:
From the third block j k _ m, we can infer that the first letter of each block is 'j' and the third letter is 'l'.
Filling this pattern j k l m into all blocks:
1st block: j k l m
2nd block: j k l m
3rd block: j k l m
The sequence of inserted letters is: j, l, j, m, l.
This matches option B (jljml).