In the neutral or faintly alkaline medium, ${\text{KMnO}}_4$ oxidises iodide into iodate. The change in oxidation state of manganese in this reaction is from:

In neutral or faintly alkaline medium, Permanganate (${\text{MnO}}_4^{-}$) acts as an oxidizing agent and is reduced to Manganese dioxide (${\text{MnO}}_2$).In ${\text{MnO}}_4^{-}$, oxidation state of $\text{Mn}$ is $+7$.In ${\text{MnO}}_2$, oxidation state of $\text{Mn}$ is $+4$.The change is from $+7$ to $+4$.