In the series $8,19,30,\dots$, what will be the 10th term?

The given series is $8,19,30,\dots$ Let's find the common difference ($d$) between consecutive terms:
$$19-8=11$$
$$30-19=11$$
Since the common difference is constant, this is an Arithmetic Progression (AP) where:First term ($a$) = $8$ Common difference ($d$) = $11$ The formula for the $n$ -th term of an AP is:
$$T_n=a+(n-1)d$$
We need to find the 10th term ($n=10$):
$$T_{10}=8+(10-1)\times 11$$
$$T_{10}=8+9\times 11$$
$$T_{10}=8+99=107$$