In $△OPQ$, $\angle O=50^{\circ }$, $\angle P=70^{\circ }$, and the bisectors of $\angle P$ and $\angle Q$ meet at $R$. Find $\angle PRQ$.

In $△OPQ$, the point $R$ where the angle bisectors of $\angle P$ and $\angle Q$ meet is the incenter of the triangle.The angle formed at the incenter $R$ opposite to vertex $O$ is given by the formula:
$$\angle PRQ=90^{\circ }+\frac{1}{2}\angle O$$
Given $\angle O=50^{\circ }$:
$$\angle PRQ=90^{\circ }+\frac{1}{2}(50^{\circ })$$
$$\angle PRQ=90^{\circ }+25^{\circ }=115^{\circ }$$