In which of the following ionization processes, the bond order has increased and the magnetic behaviour has changed?

1. $\text{NO}$: Total electrons = $7+8=15$. Configuration: $\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\ast }2s^2\sigma 2p_z^2\pi 2p_x^2\pi 2p_y^2{\pi }^{\ast }2p_x^1$.Bond Order = $\frac{10-5}{2}=2.5$. It is paramagnetic due to 1 unpaired electron.2. ${\text{NO}}^{+}$: Total electrons = $14$. Configuration: same as ${\text{N}}_2$ ($\dots \pi 2p_x^2\pi 2p_y^2$).Bond Order = $\frac{10-4}{2}=3$. It is diamagnetic (all electrons paired).In the process $\text{NO}\to {\text{NO}}^{+}$, an electron is removed from an anti-bonding molecular orbital (${\pi }^{\ast }$), which increases the bond order and changes magnetic behavior from paramagnetic to diamagnetic.