Joy and Kat run around a circular track of length 1100 m in opposite directions with initial speed of 6 m/sec and 4 m/sec, respectively. Starting from the same point whenever they meet, Joy's speed halves and Kat's speed doubles. After how much time from the beginning will they meet for the second time?
- A220 sec
- B210 sec
- C190 sec
- D200 sec
Solution & Step-by-step Explanation
Step 1: First Meeting
Total distance to cover for the first meeting = length of the track = 1100 m
Initial speed of Joy (S
J
) = 6 m/sec
Initial speed of Kat (S
K
) = 4 m/sec
Since they run in opposite directions, their relative speed is:
Relative Speed
1
=S
J
+S
K
=6+4=10 m/sec
Time taken for the first meeting (T
1
):
T
1
=
Relative Speed
1
Distance
=
10
1100
=110 sec
Step 2: Second Meeting
Immediately after the first meeting, Joy's speed halves:
New S
J
=
2
6
=3 m/sec
Kat's speed doubles:
New S
K
=4×2=8 m/sec
Their new relative speed in opposite directions is:
Relative Speed
2
=3+8=11 m/sec
Time taken from the first meeting to the second meeting (T
2
):
T
2
=
Relative Speed
2
Distance
=
11
1100
=100 sec
Step 3: Total Time
Total time from the beginning until the second meeting:
Total Time=T
1
+T
2
=110+100=210 sec
Total distance to cover for the first meeting = length of the track = 1100 m
Initial speed of Joy (S
J
) = 6 m/sec
Initial speed of Kat (S
K
) = 4 m/sec
Since they run in opposite directions, their relative speed is:
Relative Speed
1
=S
J
+S
K
=6+4=10 m/sec
Time taken for the first meeting (T
1
):
T
1
=
Relative Speed
1
Distance
=
10
1100
=110 sec
Step 2: Second Meeting
Immediately after the first meeting, Joy's speed halves:
New S
J
=
2
6
=3 m/sec
Kat's speed doubles:
New S
K
=4×2=8 m/sec
Their new relative speed in opposite directions is:
Relative Speed
2
=3+8=11 m/sec
Time taken from the first meeting to the second meeting (T
2
):
T
2
=
Relative Speed
2
Distance
=
11
1100
=100 sec
Step 3: Total Time
Total time from the beginning until the second meeting:
Total Time=T
1
+T
2
=110+100=210 sec