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for water is . If your automobile radiator holds of water, how many grams of ethylene glycol () must you add to get the freezing point of the solution lowered to ?

  1. A
  2. B
  3. C
  4. D

Solution & Step-by-step Explanation

$
\text{C}_2\text{H}_6\text{O}_2 = 2(12) + 6(1) + 2(16) = 24 + 6 + 32 = 62\,\text{g/mol} $

Closest option is .

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for water is . If your automobile radiator holds of water, how many grams of ethylene glycol () must you add to get the freezing point of the solution lowered to ?
A
B
C
D

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