K is 5 years older to H. H is 3 years younger to R. R is 6 years older to C. C is 7 years younger to L. Who is the eldest?
- AH
- BK
- CR
- DL
Solution & Step-by-step Explanation
Let us write the relationships in terms of linear age equations relative to a single variable or compare directly:
K=H+5⟹H=K−5
H=R−3⟹R=H+3
Substituting H=K−5:
R=(K−5)+3=K−2⟹K=R+2
(So K is older than R)
R=C+6⟹C=R−6
C=L−7⟹L=C+7
Substituting C=R−6:
L=(R−6)+7=R+1
Now let us compare all ages relative to R:
R=R
K=R+2
H=R−3
C=R−6
L=R+1
Comparing the values: R+2>R+1>R>R−3>R−6, which translates to:
K>L>R>H>C
Therefore, K is the eldest.
K=H+5⟹H=K−5
H=R−3⟹R=H+3
Substituting H=K−5:
R=(K−5)+3=K−2⟹K=R+2
(So K is older than R)
R=C+6⟹C=R−6
C=L−7⟹L=C+7
Substituting C=R−6:
L=(R−6)+7=R+1
Now let us compare all ages relative to R:
R=R
K=R+2
H=R−3
C=R−6
L=R+1
Comparing the values: R+2>R+1>R>R−3>R−6, which translates to:
K>L>R>H>C
Therefore, K is the eldest.