Let I be a 100-dimensional identity matrix and E be the set of its distinct (no value appears more than once in E) real eigenvalues. The number of elements in E is .
Correct Answer
1-1
Solution & Step-by-step Explanation
Explanation:
The 100-dimensional identity matrix will have 1 as the diagonal elements and all the other elements as zero.
That implies the eigenvalue is only 1.
Now E is the set of its distinct (no value appears more than once in E) real eigenvalues.
⇒ E = {1}
So number of distinct elements in E is 1.
The 100-dimensional identity matrix will have 1 as the diagonal elements and all the other elements as zero.
That implies the eigenvalue is only 1.
Now E is the set of its distinct (no value appears more than once in E) real eigenvalues.
⇒ E = {1}
So number of distinct elements in E is 1.