Let T_1 and T_2 be the energy of an electron in the first and second excited states of hydrogen atom, respectively. According to the Bohr’s model of a - Physics MCQ NEET 2022 2026 | ExamTest.live

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Let T_{1} and T_{2} be the energy of an electron in the first and second excited states of hydrogen atom, respectively. According to the Bohr’s model of an atom; the ratio T_{1} : T_{2} is:

Solution & Step-by-step Explanation

In Bohr's model, the energy of an electron in the n^{t h} orbit is: E_{n} \propto \frac{1}{n ^{2}} The "first excited state" corresponds to n = 2 .The "second excited state" corresponds to n = 3 .Therefore, T_{1} = E_{2} and T_{2} = E_{3} . \frac{T _{1}}{T _{2}} = \frac{E _{2}}{E _{3}} = \frac{1/ 2 ^{2}}{1/ 3 ^{2}} = \frac{1/4}{1/9} = \frac{9}{4} Thus, T_{1} : T_{2} = 9 : 4 .

Try it yourself before checking the explanation above.

Let T_{1} and T_{2} be the energy of an electron in the first and second excited states of hydrogen atom, respectively. According to the Bohr’s model of an atom; the ratio T_{1} : T_{2} is:

1 : 4

4 : 1

4 : 9

9 : 4

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