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mediumNATPYQs Based test 27: General AptitudeGeneral Aptitude
1 mark (−0.33)

Let X be a continuous random variable denoting the temperature measured. The range of temperature is [0, 100] degree Celsius and let the probability density function of X be f(x) = 0.01 for 0 ≤ X ≤ 100.

The mean of X is ______

Correct Answer

Solution & Step-by-step Explanation

This question asks us to find the mean of a continuous random variable, denoted as X, which represents temperature. We are given the range of temperature as [0, 100] degrees Celsius and its probability density function (PDF), , for . This type of PDF, where the probability is constant over a specific interval, represents a uniform distribution.

Mean Calculation Formula for Continuous Variables

The mean, or expected value, of a continuous random variable X with a probability density function over the interval is calculated using the integral:



Applying the PDF and Range

In this specific problem:

- The lower limit of the range is .
- The upper limit of the range is .
- The probability density function is .

Substituting these values into the formula, we get:



Step-by-Step Integration

To find the mean, we perform the integration:

1. Factor out the constant :
2. Integrate with respect to . The integral of is :
3. Evaluate the definite integral using the limits and :
4. Calculate the values:
5. Calculate the final result:

Verification of PDF

Before concluding, it's good practice to ensure the PDF is valid by checking if its integral over the entire range equals 1:





Since the integral equals 1, the PDF is valid.

Final Mean Value

The calculated mean of the continuous random variable X, representing the temperature, is 50.0 degrees Celsius.

Practice this question

Try it yourself before checking the explanation above.

Let X be a continuous random variable denoting the temperature measured. The range of temperature is [0, 100] degree Celsius and let the probability density function of X be f(x) = 0.01 for 0 ≤ X ≤ 100.

The mean of X is ______

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