M, N, O, P, Q and R are sitting around a circular table facing the centre.
* O is an immediate neighbour of M.
* Only two people sit between O and Q.
* P sits second to the left of R.
* N is an immediate neighbour of P.
Who is sitting second to the right of M?

Let's create the arrangement step-by-step around a circular table with 6 positions (numbered 1 to 6 in a counter-clockwise direction):
1. Place O at position 1.
2. Since exactly two people sit between O and Q in a 6-person circle, Q must sit directly opposite to O. Thus, Q is at position 4.
3. O is an immediate neighbour of M, so M can be at position 2 or position 6. Let's test the configurations:
* If M is at position 2, the available positions left are 3, 5, and 6.
* We are given that P sits second to the left of R. Facing the center, moving clockwise means moving to the left. If R is placed at position 3, moving 2 slots clockwise brings us to position 5, so P is at position 5.
* The remaining position 6 must be occupied by N.
* Let's check the last condition: "N is an immediate neighbour of P". Since P is at 5 and N is at 6, they are neighbors. This configuration is perfectly valid.
* (Note: Placing M at position 6 would lead to a contradiction where N cannot be an immediate neighbor of P).

The finalized counter-clockwise position order (1 to 6) is:

* 1: O, 2: M, 3: R, 4: Q, 5: P, 6: N

We need to find who sits second to the right of M (Position 2). Moving counter-clockwise means moving to the right.

* First to the right of M is O (Position 1).
* Second to the right of M is N (Position 6).

Therefore, N is sitting second to the right of M.