Manjeet can do a work in 18 hours. If he is joined by Jaya who is 100% more efficient, in what time will they together finish the work?
- A6 hours
- B3 hours
- C12 hours
- D24 hours
Solution & Step-by-step Explanation
Let the efficiency of Manjeet be 1 unit/hour.
Since Jaya is 100% more efficient than Manjeet:
Efficiency of Jaya=1+(
100
100
×1)=2 units/hour
Manjeet completes the work in 18 hours, so:
Total Work=Efficiency of Manjeet×Time=1×18=18 units
Combined efficiency of Manjeet and Jaya:
Total Efficiency=1+2=3 units/hour
Time taken by both together to finish the work:
Time=
Combined Efficiency
Total Work
=
3
18
=6 hours
Since Jaya is 100% more efficient than Manjeet:
Efficiency of Jaya=1+(
100
100
×1)=2 units/hour
Manjeet completes the work in 18 hours, so:
Total Work=Efficiency of Manjeet×Time=1×18=18 units
Combined efficiency of Manjeet and Jaya:
Total Efficiency=1+2=3 units/hour
Time taken by both together to finish the work:
Time=
Combined Efficiency
Total Work
=
3
18
=6 hours