Mohan divides 18935 by a certain number. If the quotient and the remainder he gets are 102 and 65, respectively, then the divisor is:

According to the division algorithm:
Dividend=(Divisor×Quotient)+Remainder
Given:

Dividend=18935

Quotient=102

Remainder=65

Let the divisor be d.

18935=(d×102)+65
18935−65=102d
18870=102d
d=
102
18870
​

Dividing both numerator and denominator by 6:

d=
17
3145
​

d=185