Observe the following series carefully and answer the question that follows.
$$\text{C}\$1\%\text{E}721\text{@}\text{I}\ast \#\text{@}\text{A}7\ast \#>8\text{U}>$$

How many numbers are followed by an alphabet if the second half of the series is reversed?

Let's count the total number of elements in the given series:
Elements: $\text{C}$, \$,$ 1$,$ \%$,$ \text{E}$,$ 7$,$ 2$,$ 1$,$!$,$ @$,$ \text{I}$,$ \ast$,$ \#$,$ @$,$ \text{A}$,$ 7$,$ \ast$,$ \#$,$ >$,$ 8$,$ \text{U}$,$ >$.Totalnumberofelements=$ 22$.Thesecondhalfcontainsthelast$ 11$elements:$$\text{Second half}=\ast ,\#,@,\text{A},7,\ast ,\#,>,8,\text{U},>$$Reversingthesecondhalf,itbecomes:$$\text{Reversed second half}=>,\text{U},8,>,\#,\ast ,7,\text{A},@,\#,\ast$$Now,jointheunchangedfirsthalfandthereversedsecondhalf:$\text{New Series} = \text{C}, \, 1, \%, \text{E}, 7, 2, 1, !, @, \text{I}, >, \text{U}, 8, >, \#, \ast, 7, \text{A}, @, \#, \ast
$$Weneedtofindthenumbersthatareimmediatelyfollowedbyanalphabet(Number$ \rightarrow$Alphabet):\ast Le{t}^{\prime }scheckeachnumber:\ast$ 1$isfollowedby$ \%$(Notanalphabet)\ast$ 7$isfollowedby$ 2$(Notanalphabet)\ast$ 2$isfollowedby$ 1$(Notanalphabet)\ast$ 1$isfollowedby$!$(Notanalphabet)\ast$ 8$isfollowedby$ >$(Notanalphabet)\ast$ 7$isfollowedby$ \text{A}$(Yes!$ 7$isanumber,$ \text{A}$isanalphabet)Thereisexactly$ 1$ such instance.