One solid sphere A and another hollow sphere B are of same mass and same outer radii. Their moment of inertia about their diameters are respectively I - Physics MCQ AIEEE 2004 2026 | ExamTest.live

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One solid sphere A and another hollow sphere B are of same mass and same outer radii. Their moment of inertia about their diameters are respectively I_{A} and I_{B} such that:

Solution & Step-by-step Explanation

Moment of inertia of a solid sphere (A) is I_{A} = \frac{2}{5} M R^{2} = 0.4 M R^{2} .Moment of inertia of a thin hollow sphere (B) is I_{B} = \frac{2}{3} M R^{2} \approx 0.67 M R^{2} .Since M and R are the same for both, I_{A} < I_{B} .

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One solid sphere A and another hollow sphere B are of same mass and same outer radii. Their moment of inertia about their diameters are respectively I_{A} and I_{B} such that:

I_{A} = I_{B}

I_{A} > I_{B}

I_{A} < I_{B}

I_{A} / I_{B} = d_{A} / d_{B} (where d denotes density)

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