One ticket is selected at random from 50 tickets numbered 00, 01, 02, , 49 . Then the probability that the sum of the digits on the selected ticket is - Mathematics MCQ AIEEE 2009 2026 | ExamTest.live

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One ticket is selected at random from 50 tickets numbered 00, 01, 02, \dots, 49 . Then the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero, equals:

Solution & Step-by-step Explanation

Let S be the sample space of tickets. N (S) = 50 .Event B (product of digits is zero): {00, 01, 02, 03, 04, 05, 06, 07, 08, 09, 10, 20, 30, 40} . N (B) = 14 .Event A (sum of digits is 8): {08, 17, 26, 35, 44} . A \cap B : Only {08} . N (A \cap B) = 1 . P (A ∣ B) = \frac{N ( A \cap B )}{N ( B )} = 1/14 .

Try it yourself before checking the explanation above.

One ticket is selected at random from 50 tickets numbered 00, 01, 02, \dots, 49 . Then the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero, equals:

1/14

1/7

5/14

1/50

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