Out of 32 numbers, the average of the first 16 numbers is 54 and the average of the last 15 numbers is 57. If the 17
th
number is excluded, what will be the average of the remaining numbers (correct to one decimal place)?

Note: In this standard SSC question type, the absolute initial total average is generally missing from the problem text, but it can be uniquely derived by recognizing that the total count of numbers matches the components exactly (16+1+15=32). Let's find the required average when the 17
th
number is excluded.

Since we are excluding the 17
th
number, the remaining numbers are precisely the first 16 numbers and the last 15 numbers (total of 31 numbers).

Sum of first 16 numbers = 16×54=864
Sum of last 15 numbers = 15×57=855

Total sum of these remaining 31 numbers:

Sum
31
​
=864+855=1719
New average of the remaining 31 numbers:

Average=
31
1719
​
≈55.4516
Rounding to one decimal place gives 55.5.