P works twice as fast as Q. If Q can complete a task in 36 days independently, the number of days in which P and Q can together complete the task is:
- A12 days
- B9 days
- C16 days
- D18 days
Solution & Step-by-step Explanation
Given that P works twice as fast as Q, the ratio of their efficiencies is:
Efficiency of P:Efficiency of Q=2:1
Since efficiency is inversely proportional to time taken:
Time taken by P=
2
Time taken by Q
=
2
36
=18 days
Work done by P in 1 day =
18
1
Work done by Q in 1 day =
36
1
Together, work done by P and Q in 1 day is:
18
1
+
36
1
=
36
2+1
=
36
3
=
12
1
Thus, working together they will complete the task in 12 days.
Efficiency of P:Efficiency of Q=2:1
Since efficiency is inversely proportional to time taken:
Time taken by P=
2
Time taken by Q
=
2
36
=18 days
Work done by P in 1 day =
18
1
Work done by Q in 1 day =
36
1
Together, work done by P and Q in 1 day is:
18
1
+
36
1
=
36
2+1
=
36
3
=
12
1
Thus, working together they will complete the task in 12 days.