Parimal has done
4
1
th of a job in 10 days, Salim completes the rest of the job in 20 days. In how many days can they together do the job?
- A8 days
- B24 days
- C12 days
- D16 days
Solution & Step-by-step Explanation
Parimal completes
4
1
of the work in 10 days.
Time taken by Parimal to complete the whole work alone:
T
Parimal
=10×4=40 days
Remaining work = 1−
4
1
=
4
3
Salim completes
4
3
of the work in 20 days.
Time taken by Salim to complete the whole work alone:
T
Salim
=20×
3
4
=
3
80
days
Let total work be 80 units (LCM of 40 and
3
80
).
Efficiency of Parimal =
40
80
=2 units/day
Efficiency of Salim =
3
80
80
=3 units/day
Combined efficiency of Parimal and Salim = 2+3=5 units/day.
Time taken by both together to complete the job:
Time=
Combined Efficiency
Total Work
=
5
80
=16 days
4
1
of the work in 10 days.
Time taken by Parimal to complete the whole work alone:
T
Parimal
=10×4=40 days
Remaining work = 1−
4
1
=
4
3
Salim completes
4
3
of the work in 20 days.
Time taken by Salim to complete the whole work alone:
T
Salim
=20×
3
4
=
3
80
days
Let total work be 80 units (LCM of 40 and
3
80
).
Efficiency of Parimal =
40
80
=2 units/day
Efficiency of Salim =
3
80
80
=3 units/day
Combined efficiency of Parimal and Salim = 2+3=5 units/day.
Time taken by both together to complete the job:
Time=
Combined Efficiency
Total Work
=
5
80
=16 days