Pick out the correct statement with respect to $[\text{Mn}(\text{CN}{)}_6{]}^{3-}$:

In $[\text{Mn}(\text{CN}{)}_6{]}^{3-}$:$Mn$ is in the $+3$ oxidation state.Electronic configuration of $M{n}^{3+}=[Ar]3d^4$.${\text{CN}}^{-}$ is a strong field ligand, causing pairing of electrons.However, for a coordination number of 6, the geometry is always octahedral.With strong field ligands, the inner $d$ -orbitals are used: $d^{2}s{p}^3$ hybridization.$3d$ configuration: $\uparrow \downarrow \mid \uparrow \mid \uparrow \mid \text{vacant}\mid \text{vacant}$.The two vacant $3d$ orbitals participate in $d^{2}s{p}^3$ hybridization.