Pick the odd one out in the following:
13, 23, 33, 43, 53
- A23
- B33
- C43
- D53
Solution & Step-by-step Explanation
This question asks us to identify the number that does not follow the pattern established by the other numbers in the given sequence: 13, 23, 33, 43, 53.
Number Properties Analysis
To find the odd one out, let's examine the properties of each number in the list:
- 13: This is a prime number. It is only divisible by 1 and itself. The sum of its digits is .
- 23: This is a prime number. It is only divisible by 1 and itself. The sum of its digits is .
- 33: This is a composite number. It is divisible by 1, 3, 11, and 33. The sum of its digits is .
- 43: This is a prime number. It is only divisible by 1 and itself. The sum of its digits is .
- 53: This is a prime number. It is only divisible by 1 and itself. The sum of its digits is .
Odd Number Conclusion
Observing the properties:
- Most numbers in the sequence (13, 23, 43, 53) are prime numbers.
- The number 33 is the only composite number in the sequence.
- Alternatively, we can consider divisibility by 3. A number is divisible by 3 if the sum of its digits is divisible by 3. - For 13, the sum is 4 (not divisible by 3). - For 23, the sum is 5 (not divisible by 3). - For 33, the sum is 6 (divisible by 3). - For 43, the sum is 7 (not divisible by 3). - For 53, the sum is 8 (not divisible by 3).
Based on these observations, the number 33 stands out because it is the only composite number and the only one divisible by 3 in the given list. Therefore, 33 is the odd one out.