Raj is facing north. He cycles for 8 km, then turns towards the south-east direction to move 10 km and from there, he moves 6 km towards the west. In which direction/place is he from his original position?
- ANorth
- BEast
- CWest
- DAt the original position
Solution & Step-by-step Explanation
Let's map Raj's movements step-by-step using a Cartesian coordinate system, starting from the origin (0,0):
Starts at (0,0) facing North.
Moves 8 km North → New position is (0,8).
Turns South-East and moves 10 km.
South-East direction forms a right-angled triangle with the vertical (South) and horizontal (East) displacement.
Since he goes 10 km hypotenuse diagonally downward towards south-east from (0,8), let's check if it forms a standard (6,8,10) Pythagorean triple.
If he moves 8 km down (South) and 6 km right (East), the distance is
8
2
+6
2
=10 km.
Moving 8 km South from (0,8) brings his y-coordinate back to 8−8=0.
Moving 6 km East brings his x-coordinate to 0+6=6.
So, after moving 10 km South-East, his position is exactly (6,0).
Moves 6 km towards the West.
From (6,0), moving 6 km West means subtracting 6 from the x-coordinate: 6−6=0.
His final position is (0,0).
Thus, Raj is exactly at the original position.
Starts at (0,0) facing North.
Moves 8 km North → New position is (0,8).
Turns South-East and moves 10 km.
South-East direction forms a right-angled triangle with the vertical (South) and horizontal (East) displacement.
Since he goes 10 km hypotenuse diagonally downward towards south-east from (0,8), let's check if it forms a standard (6,8,10) Pythagorean triple.
If he moves 8 km down (South) and 6 km right (East), the distance is
8
2
+6
2
=10 km.
Moving 8 km South from (0,8) brings his y-coordinate back to 8−8=0.
Moving 6 km East brings his x-coordinate to 0+6=6.
So, after moving 10 km South-East, his position is exactly (6,0).
Moves 6 km towards the West.
From (6,0), moving 6 km West means subtracting 6 from the x-coordinate: 6−6=0.
His final position is (0,0).
Thus, Raj is exactly at the original position.