Read the following table and find the relevant code for '472938' as per the conditions given:
Conditions:
1. If both the first and last digits of the number are odd digits, then both are to be coded as 'S'.
2. If both the first and last digits of the number are even digits, then both are to be coded as 'Z'.
3. If one among the first and last digits is odd and the other one is even, then the first digit has to be coded as 'Q' and the last digit as 'W'.
- AZTWMNZ
- BKTMWNZ
- CZTMWNZ
- DKTMWNB
Solution & Step-by-step Explanation
The given number to be coded is 472938.
Let's check the conditions based on the first and last digits:
* First digit = (an even digit)
* Last digit = (an even digit)
Since both the first and last digits are even, Condition 2 applies: both must be coded as 'Z'.
Now, let's substitute the letter codes for the remaining middle digits from the table:
*
*
*
*
Combining these together, we get the final code layout:
Thus, the code is ZTMWNZ.
Let's check the conditions based on the first and last digits:
* First digit = (an even digit)
* Last digit = (an even digit)
Since both the first and last digits are even, Condition 2 applies: both must be coded as 'Z'.
Now, let's substitute the letter codes for the remaining middle digits from the table:
*
*
*
*
Combining these together, we get the final code layout:
Thus, the code is ZTMWNZ.