Referring to the P – T diagram in the previous question, the work done on the gas in taking it from D to A is: - Physics MCQ AIEEE 2009 2026 | ExamTest.live

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Referring to the P - T diagram in the previous question, the work done on the gas in taking it from D to A is:

Solution & Step-by-step Explanation

From D to A, the temperature T is constant (300 K). This is an isothermal process.Work done W_{D A} = n RT ln (P_{D} / P_{A}) .Given n = 2, T = 300 K, P_{D} = 1 \times 1 0^{5} Pa, P_{A} = 2 \times 1 0^{5} Pa . W_{D A} = 2 \times R \times 300 \times ln (1/2) = 600 R (- ln 2) W_{D A} = - 600 R \times 0.693 = - 415.8 R \approx - 414 R

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Referring to the P - T diagram in the previous question, the work done on the gas in taking it from D to A is:

- 414 R

+ 414 R

- 690 R

+ 690 R

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