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mediumMCQSSC CGL2026General Intelligence and Reasoning
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Select the combination of letters that when sequentially placed in the blanks of the given series, will complete the series.
yz_zx_xyx_z_zxzx

  1. A
    zxyxyy
  2. B
    xyzyyy
  3. C
    xyzzxy
  4. D
    xyxzxy

Solution & Step-by-step Explanation

Let's count the total number of characters, which is 18. Let's try dividing the series into repeated blocks of 3, 6, or specific structures.
Let's check Option C: xyzzxy
Substituting the letters in order into the blanks:
1st blank → x
2nd blank → y
3rd blank → z
4th blank → z
5th blank → x
6th blank → y

The complete series becomes:
x y z y z x z x y x z z x z x z x y

Let's break this into groups of 3:
xyz | yzx | zxy | xzz | xzx | zxy → No obvious repeating pattern.

Let's look at a shifting pattern or block of 6 characters:
xyz zx_ ...
Let's analyze alternative patterns:
The series can be divided into repeating cycles of three letters x,y,z:
Let's test Option D: xyxzxy
Substituting the letters:
x y z y z x x x y x z z x z x z x y → No uniform pattern.

Let's test Option A: zxyxyy
z y z x z x y x y x x z y z x z x y

Let's reconsider a block of 3 elements rotating:
xyz, yzx, zxy
If we check:
1st block: x y z
2nd block: y z x
3rd block: z x y
4th block: x y z
5th block: x z x → doesn't fit standard block.

Let's test option C carefully with groupings:
If we fill with option C: x y z | y z x | z x y | x z z | x z x | z x y
Let's verify option D (xyxzxy):
xyzyzxxxyxzzxzxzxy

Let's test option B (xyzyyy):
x y z y z x z x y x y z y z x z x y
Let's split this into blocks of 3:
1st: x y z
2nd: y z x
3rd: z x y
4th: x y z
5th: y z x
6th: z x y

This creates a perfect cyclic pattern where the group of 3 shifts by one position each time:
(x y z) → (y z x) → (z x y) → (x y z) → (y z x) → (z x y)

The blanks are filled by: x, y, z, y, y, y.
This perfectly matches Option B.

Practice this question

Try it yourself before checking the explanation above.

Select the combination of letters that when sequentially placed in the blanks of the given series, will complete the series.
yz_zx_xyx_z_zxzx
A
zxyxyy
B
xyzyyy
C
xyzzxy
D
xyxzxy

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