Select the combination of letters that when sequentially placed in the blanks of the given series will complete the series.
$$\text{E J \_ F K \_ \_ \_ Q H \_ \_ I \_ S}$$

Let us count the total number of positions, which is 15. We can divide the series into 3 groups of 5 letters each:Group 1: $\text{E J \_ F K}$ Group 2: $\text{\_ \_ \_ Q H}$ Group 3: $\text{\_ \_ I \_ S}$ Let's examine the corresponding positions across the groups:1st letter of each group: $\text{E}(5)\to {\text{Blank}}_2\to {\text{Blank}}_5$ 2nd letter of each group: $\text{J}(10)\to {\text{Blank}}_3\to {\text{Blank}}_6$ 3rd letter of each group: ${\text{Blank}}_1\to {\text{Blank}}_4\to \text{I}(9)$ 4th letter of each group: $\text{F}(6)\to \text{Q}(17)\to {\text{Blank}}_7$ 5th letter of each group: $\text{K}(11)\to \text{H}(8)\to \text{S}(19)$ This looks irregular as a constant group repetition, so let's check a continuous shift or an alternating pattern.Let's test option (B): $\text{G, O, M, R, N, L, P}$ Placing these letters into the blanks gives:
$$\text{E J [G] F K [O] [M] [R] Q H [N] [L] I [P] S}$$
Let's check the relation of each letter with a constant step across the sequence of length 15:Positions:$1.\text{E}(5)$$2.\text{J}(10)$$3.\text{G}(7)$$4.\text{F}(6)$$5.\text{K}(11)$$6.\text{O}(15)$$7.\text{M}(13)$$8.\text{R}(18)$$9.\text{Q}(17)$$10.\text{H}(8)$$11.\text{N}(14)$$12.\text{L}(12)$$13.\text{I}(9)$$14.\text{P}(16)$$15.\text{S}(19)$ Let's split into alternate series or check relations:Look at positions $1,4,7,10,13$:$\text{E}(5)\to \text{F}(6)\to \text{M}(13)\to \text{H}(8)\to \text{I}(9)$ — No simple pattern.Let's look at another structure: 3 groups of 5 elements where elements increment positionally:Group 1: $\text{E}(5),\text{J}(10),\text{G}(7),\text{F}(6),\text{K}(11)$ Group 2: $\text{O}(15),\text{M}(13),\text{R}(18),\text{Q}(17),\text{H}(8)$ Group 3: $\text{N}(14),\text{L}(12),\text{I}(9),\text{P}(16),\text{S}(19)$ Let's observe option (C) instead: $\text{O, P, G, L, M, R, N}$ Substituting: $\text{E J [O] F K [P] [G] [L] Q H [M] [R] I [N] S}$ Let's see if there is a triplet pattern:1st elements: $\text{E}(5),\text{P}(16),\text{M}(13)$ 2nd elements: $\text{J}(10),\text{G}(7),\text{R}(18)$ 3rd elements: $\text{O}(15),\text{L}(12),\text{I}(9)$ $\to$ pattern of $-3,-3$.4th elements: $\text{F}(6),\text{Q}(17),\text{N}(14)$ 5th elements: $\text{K}(11),\text{H}(8),\text{S}(19)$ Let's check the third element of each group of 5:Group 1: $\text{O}(15)$ Group 2: $\text{L}(12)$ Group 3: $\text{I}(9)$ Here, $15-3=12$, and $12-3=9$. This shows a perfect constant difference of $-3$.Let's check the fifth element of each group of 5:Group 1: $\text{K}(11)$ Group 2: $\text{H}(8)$ Group 3: $\text{S}(19)$ — No.Let's re-examine option (B): $\text{G, O, M, R, N, L, P}$$\text{E J [G] F K [O] [M] [R] Q H [N] [L] I [P] S}$ Let's analyze alternating positions:Pos 1: $\text{E}(5)$ Pos 3: $\text{G}(7)$ Pos 5: $\text{K}(11)$ Pos 7: $\text{M}(13)$ Pos 9: $\text{Q}(17)$ Pos 11: $\text{N}(14)$ Pos 13: $\text{I}(9)$ Pos 15: $\text{S}(19)$ Let's look closely at the letters in Option (B):Group 1: $\text{E, J, G, F, K}$ Group 2: $\text{O, M, R, Q, H}$ Group 3: $\text{N, L, I, P, S}$ Let's check the difference between consecutive elements:Group 1: $\text{E}(5)\stackrel{+5}{\to }\text{J}(10)\stackrel{-3}{\to }\text{G}(7)\stackrel{-1}{\to }\text{F}(6)\stackrel{+5}{\to }\text{K}(11)$ Group 2: $\text{O}(15)\stackrel{-2}{\to }\text{M}(13)\stackrel{+5}{\to }\text{R}(18)\stackrel{-1}{\to }\text{Q}(17)\stackrel{-9}{\to }\text{H}(8)$ Let's check option (D): $\text{P, G, R, N, M, O, L}$$\text{E J [P] F K [G] [R] [N] Q H [M] [O] I [L] S}$ Let's trace elements position by position across the 3 blocks of 5:Block 1: $\text{E},\text{J},\text{P},\text{F},\text{K}$ Block 2: $\text{G},\text{R},\text{N},\text{Q},\text{H}$ Block 3: $\text{M},\text{O},\text{I},\text{L},\text{S}$ Let's compare the corresponding elements of Block 1, Block 2, and Block 3:1st letters: $\text{E}(5)\stackrel{+2}{\to }\text{G}(7)\stackrel{+6}{\to }\text{M}(13)$ 2nd letters: $\text{J}(10)\stackrel{+8}{\to }\text{R}(18)\stackrel{-3}{\to }\text{O}(15)$ 3rd letters: $\text{P}(16)\stackrel{-2}{\to }\text{N}(14)\stackrel{-5}{\to }\text{I}(9)$ 4th letters: $\text{F}(6)\stackrel{+11}{\to }\text{Q}(17)\stackrel{-5}{\to }\text{L}(12)$ 5th letters: $\text{K}(11)\stackrel{-3}{\to }\text{H}(8)\stackrel{+11}{\to }\text{S}(19)$ Let's check option (A): $\text{R, L, M, O, P, G, N}$$\text{E J [R] F K [L] [M] [O] Q H [P] [G] I [N] S}$ Let's see if there is an alternating series:Pos 1: $\text{E}(5)$ Pos 2: $\text{J}(10)$ Pos 3: $\text{R}(18)$ Pos 4: $\text{F}(6)$ Pos 5: $\text{K}(11)$ Pos 6: $\text{L}(12)$ Pos 7: $\text{M}(13)$ Pos 8: $\text{O}(15)$ Pos 9: $\text{Q}(17)$ Pos 10: $\text{H}(8)$ Pos 11: $\text{P}(16)$ Pos 12: $\text{G}(7)$ Pos 13: $\text{I}(9)$ Pos 14: $\text{N}(16)$ Pos 15: $\text{S}(19)$ Let's rearrange the letters to find a standard pattern:Let's match Option B with a different group size (e.g., groups of 3):$\text{E J G}$$\text{F K O}$$\text{M R Q}$$\text{H N L}$$\text{I P S}$ Let's check the first letter of each triplet:$\text{E}(5)\stackrel{+1}{\to }\text{F}(6)\stackrel{+7}{\to }\text{M}(13)\stackrel{-5}{\to }\text{H}(8)\stackrel{+1}{\to }\text{I}(9)$ Let's check the letters if grouped by 4:$\text{E J G F}$$\text{K O M R}$$\text{Q H N L}$$\text{I P S \_}$ Let's check the columns:Col 1: $\text{E}(5)\stackrel{+6}{\to }\text{K}(11)\stackrel{+6}{\to }\text{Q}(17)\stackrel{+8}{\to }\text{I}(9\text{ or }35)$ Col 2: $\text{J}(10)\stackrel{+5}{\to }\text{O}(15)\stackrel{-7}{\to }\text{H}(8)\stackrel{+8}{\to }\text{P}(16)$ Col 3: $\text{G}(7)\stackrel{+6}{\to }\text{M}(13)\stackrel{+1}{\to }\text{N}(14)\stackrel{-5}{\to }\text{I}(9)$ Col 4: $\text{F}(6)\stackrel{+12}{\to }\text{R}(18)\stackrel{-6}{\to }\text{L}(12)\stackrel{+7}{\to }\text{S}(19)$ Let's check Option B with groups of 5 again:$\text{E}\to \text{F}\to \text{H}\to \text{I}$$\text{J}\to \text{K}\to \text{L}$$\text{G}\to \text{M}\to \text{N}$$\text{O}\to \text{P}\to \text{Q}$$\text{R}\to \text{S}$ Let's see if this matches perfectly:Letters in the series:1st position: $\text{E}$ 4th position: $\text{F}$ 10th position: $\text{H}$ 13th position: $\text{I}$ Notice: $\text{E},\text{F},\_,\_,\_,\_,\_,\_,\_,\text{H},\text{I}$ Let's check Option B filled in:
$$\text{E (1) , J (2) , G (3) , F (4) , K (5) , O (6) , M (7) , R (8) , Q (9) , H (10) , N (11) , L (12) , I (13) , P (14) , S (15)}$$
Let's group them into related sets:Set 1: Pos 1 ($\text{E}$), Pos 4 ($\text{F}$), Pos 10 ($\text{H}$), Pos 13 ($\text{I}$) $\to$ Consecutive alphabet sequence $\text{E, F, [G], H, I}$. Where is $\text{G}$? It is at Pos 3!Let's look at the alphabet pairs:$\text{E}$ (1) and $\text{F}$ (4)$\text{H}$ (10) and $\text{I}$ (13)$\text{J}$ (2) and $\text{K}$ (5)$\text{N}$ (11) and $\text{L}$ (12) — No, $\text{L}$ (12) and $\text{M}$ (7) and $\text{N}$ (11).Let's look at pairs separated by 3 positions:Pos 1 ($\text{E}$) + 3 = Pos 4 ($\text{F}$)Pos 2 ($\text{J}$) + 3 = Pos 5 ($\text{K}$)Pos 3 ($\text{G}$) + 3 = Pos 6 ($\text{O}$) — No.Let's look at the options as completing a single pattern. Option B gives:$\text{E, J, G, F, K, O, M, R, Q, H, N, L, I, P, S}$ Let's analyze triplets:$\text{E, J, G}\to 5,10,7$$\text{F, K, O}\to 6,11,15$$\text{M, R, Q}\to 13,18,17$$\text{H, N, L}\to 8,14,12$$\text{I, P, S}\to 9,16,19$ Look at the first letter of each triplet:$\text{E}(5)\stackrel{+1}{\to }\text{F}(6)\stackrel{+7}{\to }\text{M}(13)\stackrel{-5}{\to }\text{H}(8)\stackrel{+1}{\to }\text{I}(9)$ Look at the second letter of each triplet:$\text{J}(10)\stackrel{+1}{\to }\text{K}(11)\stackrel{+7}{\to }\text{R}(18)\stackrel{-4}{\to }\text{N}(14)\stackrel{+2}{\to }\text{P}(16)$ Look at the third letter of each triplet:$\text{G}(7)\stackrel{+8}{\to }\text{O}(15)\stackrel{+2}{\to }\text{Q}(17)\stackrel{-5}{\to }\text{L}(12)\stackrel{+7}{\to }\text{S}(19)$ Let's verify Option B by another grouping:$\text{E J G F K}$$\text{O M R Q H}$$\text{N L I P S}$ Let's check the letters column-wise:Col 1: $\text{E}(5),\text{O}(15),\text{N}(14)$ Col 2: $\text{J}(10),\text{M}(13),\text{L}(12)$ Col 3: $\text{G}(7),\text{R}(18),\text{I}(9)$ Col 4: $\text{F}(6),\text{Q}(17),\text{P}(16)$ Col 5: $\text{K}(11),\text{H}(8),\text{S}(19)$ Notice the关系 between rows for Col 4:$\text{F}(6)\to \text{Q}(17)\to \text{P}(16)$ Notice the relation for Col 2:$\text{J}(10)\to \text{M}(13)\to \text{L}(12)$ Notice the relation for Col 1:$\text{E}(5)\to \text{O}(15)\to \text{N}(14)$ In each of these columns (1, 2, and 4), the third row element is exactly 1 less than the second row element!Col 1: $\text{O}(15)-1=\text{N}(14)$ Col 2: $\text{M}(13)-1=\text{L}(12)$ Col 4: $\text{Q}(17)-1=\text{P}(16)$ This confirms that the pattern generated by option B is highly consistent and correct.