Select the number from among the given options that can replace the question mark (?) in the following series.
4,10,23,67,137,?
- A187
- B409
- C209
- D150
Solution & Step-by-step Explanation
Let's find the step differences between the terms:
10−4=6
23−10=13
67−23=44
137−67=70
Let's look closely at the alternating patterns or standard multiplier rules for the series directly:
4×2+2=10
10×2+3=23
23×3−2=67
67×2+3=137
Wow! Look at this alternating multiplier rule:
Term 1 to Term 2: ×2+2
Term 2 to Term 3: ×2+3
Term 3 to Term 4: ×3−2 (Wait, let's look for a clearer pattern)
Let's recheck:
4×3−2=10
10×2+3=23
23×3−2=67
67×2+3=137
The pattern is perfectly alternating between:
(Term×3)−2
(Term×2)+3
Let's trace it carefully:
4×3−2=12−2=10
10×2+3=20+3=23
23×3−2=69−2=67
67×2+3=134+3=137
Following this logic, the next operation must be (Term×3)−2:
137×3−2=411−2=409
10−4=6
23−10=13
67−23=44
137−67=70
Let's look closely at the alternating patterns or standard multiplier rules for the series directly:
4×2+2=10
10×2+3=23
23×3−2=67
67×2+3=137
Wow! Look at this alternating multiplier rule:
Term 1 to Term 2: ×2+2
Term 2 to Term 3: ×2+3
Term 3 to Term 4: ×3−2 (Wait, let's look for a clearer pattern)
Let's recheck:
4×3−2=10
10×2+3=23
23×3−2=67
67×2+3=137
The pattern is perfectly alternating between:
(Term×3)−2
(Term×2)+3
Let's trace it carefully:
4×3−2=12−2=10
10×2+3=20+3=23
23×3−2=69−2=67
67×2+3=134+3=137
Following this logic, the next operation must be (Term×3)−2:
137×3−2=411−2=409